- #1
Big-Daddy
- 343
- 1
Let's say I put SO2 or SO32- or HSO3- in solution. I get the following equilibria:
SO2 (aq) + H2O (l) ⇔ HSO3- (aq) + H3O+ (aq) ... K1
HSO3- (aq) + H2O (l) ⇔ SO32- (aq) + H3O+ (aq) ... K2
And this equilibrium always going on:
2H2O (l) ⇔ H3O+ (aq) + OH- (aq) ... Kw
Other than that, to solve the system we would write two more equations:
Mass Balance (S): Initial Concentration of S = [SO2] + [SO32-] + [HSO3-]
Charge Balance: [H3O+] = [OH-] + [HSO3-] + 2[SO32-]
So it looks like the only real initial variable is the Initial Concentration of S that we put in our system. Then, does this mean that if we put [itex]c[/itex] M of SO2 to begin with in the solution, the equilibrium concentrations of every species would be the same as if we had put [itex]c[/itex] M of Na2SO3 or [itex]c[/itex] M of NaHSO3? And also the same as if we put [itex](1/3)c[/itex] M of Al2(SO3)3? (as the initial concentration of S placed in the solution is the same one way or the other)
SO2 (aq) + H2O (l) ⇔ HSO3- (aq) + H3O+ (aq) ... K1
HSO3- (aq) + H2O (l) ⇔ SO32- (aq) + H3O+ (aq) ... K2
And this equilibrium always going on:
2H2O (l) ⇔ H3O+ (aq) + OH- (aq) ... Kw
Other than that, to solve the system we would write two more equations:
Mass Balance (S): Initial Concentration of S = [SO2] + [SO32-] + [HSO3-]
Charge Balance: [H3O+] = [OH-] + [HSO3-] + 2[SO32-]
So it looks like the only real initial variable is the Initial Concentration of S that we put in our system. Then, does this mean that if we put [itex]c[/itex] M of SO2 to begin with in the solution, the equilibrium concentrations of every species would be the same as if we had put [itex]c[/itex] M of Na2SO3 or [itex]c[/itex] M of NaHSO3? And also the same as if we put [itex](1/3)c[/itex] M of Al2(SO3)3? (as the initial concentration of S placed in the solution is the same one way or the other)