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JTHERO
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Let me start off by saying I'm new here and I hope I did this in the format. Thank you.
Two masses, M1= 35.0 kg and M2= 38.0 kg, are connected by a rope that hangs over a pulley. The pulley is a uniform cylinder of radius 0.381 m and mass 3.5 kg. Initially M1 is on the ground and rests 2.5 m above the ground. If the system is released, use conservation of energy to determine the speed of just before it strikes the ground. Assume the pulley bearing is frictionless.
F= m*a Torque= r x F
I found the tension that M2-M1 put on the pulley.
F=(38.0-35.0)*9.8= 29.4
I'm a little lost after that. How do I find the speed of the pulley?
Homework Statement
Two masses, M1= 35.0 kg and M2= 38.0 kg, are connected by a rope that hangs over a pulley. The pulley is a uniform cylinder of radius 0.381 m and mass 3.5 kg. Initially M1 is on the ground and rests 2.5 m above the ground. If the system is released, use conservation of energy to determine the speed of just before it strikes the ground. Assume the pulley bearing is frictionless.
Homework Equations
F= m*a Torque= r x F
The Attempt at a Solution
I found the tension that M2-M1 put on the pulley.
F=(38.0-35.0)*9.8= 29.4
I'm a little lost after that. How do I find the speed of the pulley?