- #1
Mechanic
- 51
- 1
Hubble’s law tells us that the velocity of distant objects increases with distance as v = Hr. Does this mean that the farther a distant object gets the more rapidly that object will recede away from us? That is, are these distant objects accelerating away from us? Can we say
v = Hr, and so Acceleration = dv/dt =H dr/dt + r dH/dt = Hv = (H^2)r for constant H? Has such an acceleration been observed/measured?
Thanks
v = Hr, and so Acceleration = dv/dt =H dr/dt + r dH/dt = Hv = (H^2)r for constant H? Has such an acceleration been observed/measured?
Thanks