- #1
Elorm Avevor
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Is I understand it Hubble's law states that V = Hd = dx/dt
Solving this differential equation, I got d = kexp(HT) where k is an arbitrary constant.
This implies d²x/dt² = Hv = H²d and dⁿx/dtⁿ = Hⁿd.
However (at least for me), finding the value of k is a problem, for 1, it must vary from galaxy to galaxy because they are all different distances to us. It must also be small because when t tends to 0, x should tend to 0.
My questions are essentially:
Is my maths correct?
Are galaxies moving away exponentially?
Why when approximating the age of the universe do you use 1/H? because this implies galaxies have been moving at a constant velocity since their formation and I don't understand how that's possible from Hubble's law
Thank you
Solving this differential equation, I got d = kexp(HT) where k is an arbitrary constant.
This implies d²x/dt² = Hv = H²d and dⁿx/dtⁿ = Hⁿd.
However (at least for me), finding the value of k is a problem, for 1, it must vary from galaxy to galaxy because they are all different distances to us. It must also be small because when t tends to 0, x should tend to 0.
My questions are essentially:
Is my maths correct?
Are galaxies moving away exponentially?
Why when approximating the age of the universe do you use 1/H? because this implies galaxies have been moving at a constant velocity since their formation and I don't understand how that's possible from Hubble's law
Thank you