- #1
hedlund
- 34
- 0
Prove that if [tex] y = \sin^n{x} [/tex] then the only value for which [tex] y' = \sin{nx} [/tex] is for n=2. I'm think maybe Euler's formula may be useful ... [tex] \sin{x} = \frac{e^{ix}-e^{-ix}}{2i} [/tex] but I really got no good idea on how to solve it.