- #1
sapiental
- 118
- 0
the definite integral:
from a = (-pi/2) to (pi/2) f(((x^2)(sinx))/(1+x^6))dx
this is the way it seems most logic to me to set it up using substitution:
u = x
du = dx
from a = (-pi/2) to (pi/2) f(((u^2)(sinu))/(1+u^6))du
= (((-cos(u))(1/3u^3))/(u+1/7u^7))+CI know how to evaluate it from here, I just need some feedback on my substitution setup.
Thanks in advance.
from a = (-pi/2) to (pi/2) f(((x^2)(sinx))/(1+x^6))dx
this is the way it seems most logic to me to set it up using substitution:
u = x
du = dx
from a = (-pi/2) to (pi/2) f(((u^2)(sinu))/(1+u^6))du
= (((-cos(u))(1/3u^3))/(u+1/7u^7))+CI know how to evaluate it from here, I just need some feedback on my substitution setup.
Thanks in advance.