- #1
deryk
- 10
- 0
The question asked to solve this initial value problem
(2+x^2)dy/dx = x(y+3)
(2+x^2)dy/(dx*(y+3) = x
dy/[(y+3)*dx]= x/(2+x^2)
dy/(y+3) = x*dx/(2+x^2)
S dy/(y+3) = S x/(2+x^2)*dx
ln(y+3) = ?
Im not sure what to do with the RHS do I do integration by parts?
(2+x^2)dy/dx = x(y+3)
(2+x^2)dy/(dx*(y+3) = x
dy/[(y+3)*dx]= x/(2+x^2)
dy/(y+3) = x*dx/(2+x^2)
S dy/(y+3) = S x/(2+x^2)*dx
ln(y+3) = ?
Im not sure what to do with the RHS do I do integration by parts?