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IAmPat
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Homework Statement
The pulley in the illustration is a uniform disk of mass 2.40 kg and radius 0.220 m. The block applies a constant torque to the pulley, which is free to rotate without friction, resulting in an angular acceleration of magnitude 0.180 rad/s2 for the pulley. As the block falls 0.500 m, how much work does it do on the pulley?
Homework Equations
Net Torque = Inertia * [tex]\alpha[/tex]
Work = Torque * [tex]\Delta[/tex]X
The Attempt at a Solution
Mass of Pulley = 2.40kg
Radius = 0.220m
[tex]\alpha[/tex] = 0.180 rad/s2
I = [tex]\sum[/tex]m * r2
I = 2.40kg * (0.220)2
I = 0.1161
[tex]\sum[/tex]T = I * [tex]\alpha[/tex] = (0.11616) *(0.180)
T = 0.02091
[tex]\Delta[/tex] theta = (Change in X)/R = 0.500/0.220= 2.27
W = T * (Change in Theta) = (0.02091)(2.27)
W = 0.0475 J
I must have made a mistake somewhere.