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stryker23
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Linear Motion --Velocity and Acceleration
[10] A toy car travels along a straight line. Its position x varies with time as shown on the x-t graph. The equation of motion in the A-C interval is given by
x(t)=alpha+(beta)t^2+y(t)^(1/2)
where alpha=1.0 m, beta=1.3 m/s^2 and y=0.3 m/s^(1/2) . The curve in the interval C-E is a symmetric parabola, and the graph in the E-G interval is linear.
a) Write the equations for v(t) and a(t) in the A-C interval. Calculate the velocity in point C.
b) Calculate the accelerations in the intervals C-D and D-E, and the position in point D.
x(t)=alpha+(beta)t^2+y(t)^(1/2)
There is a graph but I do not know how to show it.
I really just want to make sure I am starting this correctly. For part (A) I filled in the given values and then took the first and second derivative to find the the velocity and the acceleration. Is that correct for this problem? The second part of a A asks for the velocity at C. "t" at "C" equals one so I took v(1). The answer I worked out was v(1)=(-2.6m/s^2)+(0.15m/s^(1/2)). This doesn't seem right to me. Could someone check to see if I am doing this the correct way? I do not know how to proceed at all with part B, so I would greatly appreciate a little direction.
Thank you.
Homework Statement
[10] A toy car travels along a straight line. Its position x varies with time as shown on the x-t graph. The equation of motion in the A-C interval is given by
x(t)=alpha+(beta)t^2+y(t)^(1/2)
where alpha=1.0 m, beta=1.3 m/s^2 and y=0.3 m/s^(1/2) . The curve in the interval C-E is a symmetric parabola, and the graph in the E-G interval is linear.
a) Write the equations for v(t) and a(t) in the A-C interval. Calculate the velocity in point C.
b) Calculate the accelerations in the intervals C-D and D-E, and the position in point D.
Homework Equations
x(t)=alpha+(beta)t^2+y(t)^(1/2)
There is a graph but I do not know how to show it.
The Attempt at a Solution
I really just want to make sure I am starting this correctly. For part (A) I filled in the given values and then took the first and second derivative to find the the velocity and the acceleration. Is that correct for this problem? The second part of a A asks for the velocity at C. "t" at "C" equals one so I took v(1). The answer I worked out was v(1)=(-2.6m/s^2)+(0.15m/s^(1/2)). This doesn't seem right to me. Could someone check to see if I am doing this the correct way? I do not know how to proceed at all with part B, so I would greatly appreciate a little direction.
Thank you.