- #1
JanClaesen
- 56
- 0
I'm trying to express the polar rose as an implicit function:
r(t)=sin t
x = sin t * cos t
y = sin^2 t
Since sin t * cos t = (1/2) * sin 2t and sin^2 t = (1/2) * (1-cos 2t)
(2x)^2 + (1-2y)^2 = 1
4x^2 -4y + 4y^2 = 0
When I plot this, Maple plots a circle, where have I gone wrong?
r(t)=sin t
x = sin t * cos t
y = sin^2 t
Since sin t * cos t = (1/2) * sin 2t and sin^2 t = (1/2) * (1-cos 2t)
(2x)^2 + (1-2y)^2 = 1
4x^2 -4y + 4y^2 = 0
When I plot this, Maple plots a circle, where have I gone wrong?