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A closed cubical box made of aluminum sheet floats in water with (1/4) of the volume above water. Determine the thickness of the sheet.
I first found out what the density would need to be for this orientation:
75% below water or
X % = density of box/ density of water
.75 = p/(1000)
p = 750 kg/m^3 --> effective density.
p = M(sheet) / Volume(box)
Mass of the sheet is then = 6p(s^2)x
where s is the length of a side of the cube, x is the thickness of the sheet and p is the density of aluminum (2700 kg/m^3)
M = 16200 x(s^2)
Therefore: 750 = 16200 x(s^2) / s^3
.0463 = x/s
The problem is, there seems to be not enough information.
I first found out what the density would need to be for this orientation:
75% below water or
X % = density of box/ density of water
.75 = p/(1000)
p = 750 kg/m^3 --> effective density.
p = M(sheet) / Volume(box)
Mass of the sheet is then = 6p(s^2)x
where s is the length of a side of the cube, x is the thickness of the sheet and p is the density of aluminum (2700 kg/m^3)
M = 16200 x(s^2)
Therefore: 750 = 16200 x(s^2) / s^3
.0463 = x/s
The problem is, there seems to be not enough information.