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help: trigonometric equation |
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| Jan19-06, 05:16 PM | #1 |
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help: trigonometric equation
[tex]x_1(cos\alpha-1) + x_2sin\alpha = 0 [/tex]
[tex]x_1sin\alpha + x_2(-cos\alpha-1) = 0 [/tex] How to solve this equation? Can anyone help me? |
| Jan20-06, 03:29 AM | #2 |
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Mentor
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It's a system of equations: 2 equations in 2 unknowns. That means you can solve it. Just solve for one unknown in terms of the other using the first equation, and then subsitute that into the second.
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| Jan20-06, 05:24 AM | #3 |
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Let me try...
Solve equation 1: [tex]x_2 = \frac{-x_1(cos\alpha - 1)}{sin\alpha}[/tex] Substitute it to the second: [tex]x_1sin\alpha + \frac{-x_1(cos\alpha - 1)}{sin\alpha}(-cos\alpha-1) = 0[/tex] [tex]x_1sin\alpha + \frac{x_1(cos^2\alpha - 1)}{sin\alpha} = 0[/tex] [tex]2x_1sin\alpha = 0[/tex] What is the solutions for [tex]2x_1sin\alpha = 0[/tex]? Obviously one is [tex]x_1=0[/tex], but if [tex]sin\alpha = 0[/tex], then... |
| Jan20-06, 05:46 AM | #4 |
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help: trigonometric equationNotice, by the way, that if [tex]sin\alpha= 0[/tex], your first step, dividing by that, would be invalid. You have to look at this case separately. If [tex]sin\alpha= 0[/tex], then [tex]cos\alpha[/tex] is either 1 or -1. What do your equations look like if [tex]sin\alpha= 0[/tex] and [tex]cos\alpha= 1[/tex]? What do your equations look like if [tex]sin\alpha= 0[/tex] and [tex]cos\alpha= -1[/tex]? |
| Jan20-06, 06:36 AM | #5 |
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HallsofIvy, thanks.
I just try another solution. Rewrite the equations: [tex](x_1cos\alpha + x_2sin\alpha) - x_1 = 0 [/tex] [tex](x_1sin\alpha - x_2cos\alpha) - x_2 = 0 [/tex] Suppose [tex]x_1 = cos\frac{\alpha}{2}, x_2 = sin\frac{\alpha}{2}[/tex], then [tex]cos\frac{\alpha}{2}cos\alpha + sin\frac{\alpha}{2}sin\alpha - cos\frac{\alpha}{2} = 0 [/tex] [tex]cos\frac{\alpha}{2}sin\alpha - sin\frac{\alpha}{2}cos\alpha - sin\frac{\alpha}{2} = 0 [/tex] It works! I am wondering whether there is some general method to solve [tex]x_1, x_2[/tex] depending on [tex]\alpha[/tex] or not. |
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