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Integrated rate law 
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#1
Jun406, 05:50 AM

P: 123

this seems a fairly straight forward qn but the ans at the back of the book does not agree with my ans :(
we have a rate constant 5e2 mol/L inital concentration of 1e3 M calculate concentration after the time elapsed is 5e3 s my ans is 7.5e4 but the ans at the back claims it is 2.5e4 formula i using is the integrated rate law [A] = kt + [A initial] did i miss something? 


#2
Jun406, 02:15 PM

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PF Gold
P: 1,198

The units of your rate constant aren't correct. It should be mole L1 sec1.
Since it's a zero order reaction, your rate law is correct. Check your calculations. 


#3
Jun906, 04:22 AM

P: 123




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