| Thread Closed |
Integrated rate law |
Share Thread |
| Jun4-06, 05:50 AM | #1 |
|
|
Integrated rate law
this seems a fairly straight forward qn but the ans at the back of the book does not agree with my ans :(
we have a rate constant 5e-2 mol/L inital concentration of 1e-3 M calculate concentration after the time elapsed is 5e-3 s my ans is 7.5e-4 but the ans at the back claims it is 2.5e-4 formula i using is the integrated rate law [A] = -kt + [A initial] did i miss something? |
| Jun4-06, 02:15 PM | #2 |
|
|
The units of your rate constant aren't correct. It should be mole L-1 sec-1.
Since it's a zero order reaction, your rate law is correct. Check your calculations. |
| Jun9-06, 04:22 AM | #3 |
|
|
|
| Thread Closed |
Similar discussions for: Integrated rate law
|
||||
| Thread | Forum | Replies | ||
| Integrated MSc in physics | Academic Guidance | 26 | ||
| Functions that cannot be integrated | Calculus | 24 | ||
| How to find the integrated rate law? | Biology, Chemistry & Other Homework | 4 | ||
| Woohoo I have integrated Lnx | General Discussion | 0 | ||
| Choosing what's integrated | Calculus | 2 | ||