Register to reply

Integrated rate law

by Ukitake Jyuushirou
Tags: integrated, rate
Share this thread:
Ukitake Jyuushirou
#1
Jun4-06, 05:50 AM
P: 123
this seems a fairly straight forward qn but the ans at the back of the book does not agree with my ans :(

we have a rate constant 5e-2 mol/L

inital concentration of 1e-3 M

calculate concentration after the time elapsed is 5e-3 s

my ans is 7.5e-4 but the ans at the back claims it is 2.5e-4

formula i using is the integrated rate law [A] = -kt + [A initial]

did i miss something?
Phys.Org News Partner Science news on Phys.org
Apple to unveil 'iWatch' on September 9
NASA deep-space rocket, SLS, to launch in 2018
Study examines 13,000-year-old nanodiamonds from multiple locations across three continents
siddharth
#2
Jun4-06, 02:15 PM
HW Helper
PF Gold
siddharth's Avatar
P: 1,197
The units of your rate constant aren't correct. It should be mole L-1 sec-1.
Since it's a zero order reaction, your rate law is correct. Check your calculations.
Ukitake Jyuushirou
#3
Jun9-06, 04:22 AM
P: 123
Quote Quote by siddharth
The units of your rate constant aren't correct. It should be mole L-1 sec-1.
Since it's a zero order reaction, your rate law is correct. Check your calculations.
yea, thanks i manage to fig this one out :D


Register to reply

Related Discussions
Integrated MSc in physics Academic Guidance 26
Functions that cannot be integrated Calculus 24
How to find the integrated rate law? Biology, Chemistry & Other Homework 4
Woohoo I have integrated Lnx General Discussion 0
Choosing what's integrated Calculus 2