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Integrated rate law

by Ukitake Jyuushirou
Tags: integrated, rate
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Ukitake Jyuushirou
#1
Jun4-06, 05:50 AM
P: 123
this seems a fairly straight forward qn but the ans at the back of the book does not agree with my ans :(

we have a rate constant 5e-2 mol/L

inital concentration of 1e-3 M

calculate concentration after the time elapsed is 5e-3 s

my ans is 7.5e-4 but the ans at the back claims it is 2.5e-4

formula i using is the integrated rate law [A] = -kt + [A initial]

did i miss something?
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siddharth
#2
Jun4-06, 02:15 PM
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The units of your rate constant aren't correct. It should be mole L-1 sec-1.
Since it's a zero order reaction, your rate law is correct. Check your calculations.
Ukitake Jyuushirou
#3
Jun9-06, 04:22 AM
P: 123
Quote Quote by siddharth
The units of your rate constant aren't correct. It should be mole L-1 sec-1.
Since it's a zero order reaction, your rate law is correct. Check your calculations.
yea, thanks i manage to fig this one out :D


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