
#1
Jan1707, 07:28 PM

P: 218

Here is the problem:
Show that if [tex]c[/tex] is a curve with [tex]\kappa=\frac{1}{r}[/tex] (r is a positive constant) that [tex]c[/tex] is moving on a circle of radius r. He gives a hunt to use the formula [tex]E(s)=C(s)+rN(s)[/tex]. I don't know where he got this equations and I have no idea what the function E is supposed to represent. I'm sure C and S are position and arclength respectively. So first I showed that [tex]\frac{dE}{ds}=0[/tex] with the definitions of T and N vectors as related to curvature K. Then he gives a hint to show [tex]absolute value(CE)=r[/tex] which I have no idea how to show, and then from that to explain why that makes C a circle or radius r? I know that the equation for a circle is nx^2+ny^2=r^2 but I don't see where that will get me here. Any help? I know this isn't in the correct format but this is more of a rigorous proof than a problem with given information... 


Register to reply 
Related Discussions  
simple circle circle collision detection  General Math  6  
Symmetry of a circle proof  Introductory Physics Homework  8  
Circle Proof  Calculus & Beyond Homework  2  
:frown: Normal curvature integral proof  Calculus & Beyond Homework  1  
Geodesic Curvature (Curvature of a curve)  Differential Geometry  8 