Register to reply

Gauss's Law / Electric Field

by jesuslovesu
Tags: electric, field, gauss
Share this thread:
May16-07, 08:50 AM
P: 201
1. The problem statement, all variables and given/known data
A very large flat aluminum plate of area A has a total charge Q over its surface. The same charge is placed over the upper surface of a glass plate. Compare the electric fields.

2. Relevant equations

3. The attempt at a solution
I know how to get the electric field of the aluminum plate.
[tex]\sigma[/tex] = Q/A
2EA = [tex]\sigma[/tex]A/e0
E = [tex]\sigma[/tex]/2e0

For the glass plate, I'm not so sure... Initially I would think E = [tex]\sigma[/tex]/e0, but it isn't...
Phys.Org News Partner Science news on
Bees able to spot which flowers offer best rewards before landing
Classic Lewis Carroll character inspires new ecological model
When cooperation counts: Researchers find sperm benefit from grouping together in mice
Doc Al
May16-07, 09:25 AM
Doc Al's Avatar
P: 41,323
Realize that the aluminum plate is a conductor.

Register to reply

Related Discussions
1.) Net electric field and 2.) Maximum electric field from centre of a ring Introductory Physics Homework 7
Electric field in a dielectric in terms of the electric field in the vacuum Introductory Physics Homework 0
Using Gauss's law to calculate magnitude of electric field Advanced Physics Homework 3
Gauss's law and the Electric field in an object General Physics 18
Gauss's Law and E field problem Introductory Physics Homework 1