Gauss's Law / Electric Field

by jesuslovesu
Tags: electric, field, gauss
 P: 202 1. The problem statement, all variables and given/known data A very large flat aluminum plate of area A has a total charge Q over its surface. The same charge is placed over the upper surface of a glass plate. Compare the electric fields. 2. Relevant equations 3. The attempt at a solution I know how to get the electric field of the aluminum plate. $$\sigma$$ = Q/A 2EA = $$\sigma$$A/e0 E = $$\sigma$$/2e0 For the glass plate, I'm not so sure... Initially I would think E = $$\sigma$$/e0, but it isn't...
 Mentor P: 40,239 Realize that the aluminum plate is a conductor.

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