
#1
Apr208, 02:46 AM


#2
Apr208, 06:38 PM

P: 33

I haven't had a great deal to do with moment vectors to this extent, but if your tutor has told you to treat the moments like forces maybe he is implying that to find the moment about the axis paralell to AB (I the moment producing the torsion in that member), then my guess would be to find the dot product of the moment you have found with the unit vector or dirrectional vector (what ever you like to call it of AB)
That is, Mab=(i2j) dot (0.6i+0.8j)=(0.6+1.6)=2.2 Mbc could be found in the same way? Sorry I couldn't be of more help, might be something for you to have a look at anyway. Elbarto 



#3
Apr308, 12:44 AM

P: 3

i've had a look at something from one of last year's courses and i think you're right... cheers elbarto... very helpful



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