Mastering the Mysteries of Logarithms: Solving for x in a Tricky Equation

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DeanBH
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i've got a logashizm problem to this point

the log is base 2log (x(x+3)^2 / (4x+2)) = 1

apparently x(x+3)^2 / (4x+2) = 2

no idea why, halp?

thxgod damn it, nvm

2^1 = (x(x+3)^2 / (4x+2)) when you take the damn log out.
 
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exactly
 

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