# Iron bar bending force

by cooper1
Tags: geometry, material, physics, solid
 P: 208 I'm not sure, but I think that you need a second moment of inertia over here, which is defined as $$I = \int r^2\, dA$$ where the are is perpendicular to the axis of bending. The bigger this moment of inertia is, the harder it is to bend or deform the beam, so you just use proportion to find what you need.