Arc Length in Parametric equation

[perpetium]

I know this is very simple, but the end integral just kills me

Homework Statement

Given equation in Parametric form
x=\sqrt{2t+1}), y=6t
Find arc length

Homework Equations

The Attempt at a Solution

take x' & y'
then Take integral of \int\sqrt{1/(2t+1) + 36}

This is where I got stuck ...is there a simple way to solve this integral ?
Thank you

 

[Defennder]

You didn't specify the limits of t for which the arc length is to be evaluated. You can try an alternatve approach here. Note that you can easily express the graph in the form y = f(x). Do that, and use the other formula to calculate arc length. Should be easier to integrate. Also remember to find the values of x for which the arc length is to be calculated.

 

[perpetium]

Defennder thanks for response
I have already evaluated that integral in the y=f(x) form, through trigonometric substitution

Now I need to evaluate it in parametric form...