| Thread Closed |
Laurent series expansion |
Share Thread | Thread Tools |
| Apr14-10, 08:47 AM | #1 |
|
|
Laurent series expansion
[b]1. I am trying to calculate the laurent series expansion of the function 1/(1-z)² in the region 1<|z|
[b]2. None [b]3. I can get an answer informally by doing the polynomial division like in high school, but I don't know if this is the right answer and in case it is I cannot prove it. Any help would be largely appreciated. |
| Apr14-10, 12:22 PM | #2 |
|
|
Recall that if a function is analytic on a domain, then its Laurent series and Taylor series are identical. Do you know how to do the Taylor series expansion?
|
| Thread Closed |
| Thread Tools | |
Similar Threads for: Laurent series expansion
|
||||
| Thread | Forum | Replies | ||
| Laurent Expansion of sin(1-1/z) | Calculus & Beyond Homework | 3 | ||
| Another Laurent Expansion Question | Calculus & Beyond Homework | 1 | ||
| Laurent series expansion help... | Calculus & Beyond Homework | 1 | ||
| Laurent Series expansion for the following function | Calculus & Beyond Homework | 6 | ||
| Laurent Expansion | Calculus & Beyond Homework | 5 | ||