Solving trigonometric equation

AI Thread Summary
To solve the trigonometric equation starting from sin C = 2/√29, the key is recognizing that C = 1/2 sin^(-1)(20/29) is equivalent to sin(2C) = 20/29. This relationship allows for the transformation of the equation into a more manageable form. The hints provided emphasize the connection between the sine function and its inverse. The discussion concludes with the participant confirming their understanding of the solution.
thereddevils
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This is part of the identity proving question .

from \sin C=\frac{2}{\sqrt{29}} , how can i reach C=\frac{1}{2}\sin^{-1} (\frac{20}{29}) ?
 
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Hi thereddevils! :smile:

(have a square-root: √ and try using the X2 tag just above the Reply box :wink:)

Hint: C = 1/2 sin-1 20/29 is the same as sin2C = 20/29 :wink:
 


tiny-tim said:
Hi thereddevils! :smile:

(have a square-root: √ and try using the X2 tag just above the Reply box :wink:)

Hint: C = 1/2 sin-1 20/29 is the same as sin2C = 20/29 :wink:


got it thanks !
 

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