Angle of refraction of light in water

AI Thread Summary
A ray of yellow light strikes a pond's surface at a 60° angle of incidence, and the refractive index of water is given as 1.33. The initial calculation incorrectly used the angle of incidence instead of the sine of the angle in the formula for refraction. The correct approach involves using the equation μ = sin(angle of incidence) / sin(angle of refraction), leading to sin r = sin(60°) / 1.33. This calculation results in an angle of refraction of approximately 40.62°, confirming the online sources. The error was clarified, and the correct methodology was established.
Kaldanis
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Homework Statement


A ray of pure yellow light reaches the surface of a pond at an angle of incidence of 60°. What angle does it make with the normal inside the water?

Speed of light in air = 300,000,000 m/s
Speed of light in water = 225,000,000 m/s
So the Refractive index μ = 1.33

Homework Equations


μ = angle of incidence / angle of refraction


The Attempt at a Solution


μ = sin i / sin r
1.33 = 60° / sin r
sin r = 60° / 1.33

So the angle of refraction equals 45.11°. Is this correct? I believe this is the correct way to work it out, yet when I check the answer online using various calculators the answer comes up as 40.62°. Am I doing something wrong?
 
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Kaldanis said:

Homework Statement


A ray of pure yellow light reaches the surface of a pond at an angle of incidence of 60°. What angle does it make with the normal inside the water?

Speed of light in air = 300,000,000 m/s
Speed of light in water = 225,000,000 m/s
So the Refractive index μ = 1.33

Homework Equations


μ = angle of incidence / angle of refraction


The Attempt at a Solution


μ = sin i / sin r
1.33 = 60° / sin r
sin r = 60° / 1.33

So the angle of refraction equals 45.11°. Is this correct? I believe this is the correct way to work it out, yet when I check the answer online using various calculators the answer comes up as 40.62°. Am I doing something wrong?
yes, you are. And the problem is shown in your writing "μ = angle of incidence / angle of refraction" when it should be "μ = sin(angle of incidence) / sin(angle of refraction)"

You write that below but then you write "1.33= 60°/ sin r" and "sin r= 60°/1.33= 45.11°"

sin r= sin(60°)/1.33. Use a calculator to determine sin(60°) and once you have sin r, use a calculator again to determine r itself.
 
HallsofIvy said:
yes, you are. And the problem is shown in your writing "μ = angle of incidence / angle of refraction" when it should be "μ = sin(angle of incidence) / sin(angle of refraction)"

You write that below but then you write "1.33= 60°/ sin r" and "sin r= 60°/1.33= 45.11°"

sin r= sin(60°)/1.33. Use a calculator to determine sin(60°) and once you have sin r, use a calculator again to determine r itself.
Ah, I see now. Sin r = 0.6511469, so r = 40.62°

Thank you sir!
 
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