Electric charge of a thin rod

[rasanders22]

Electric charge is distributed uniformly along a thin rod of length a, with total charge Q. Take the potential to be zero at infinity. Find the potential at the following points: P is distance x from (0,0) which is the right side of the rod.

Find the potential at the point P, a distance to the right of the rod.
already answered

In part A, what does your result reduce to as x becomes much larger than a?
answer from A.
Q/a4pi(e0)(ln(x+a)-ln(x)

So as x becomes larger than a, (moves toward infinity)V should reduce to zero. The ln's should cancel each other out, leaving you to multiply by 0. Except 0 is not excepted.
Ive tried
KQ(ln(x)-ln(x))
0
KQ0
According to the software, the answer depends on x, and does not depent on a.

 

[anathema]

As x becomes larger than a, the potential at point P will approach zero, as the distance between point P and the rod becomes insignificant compared to the distance between point P and infinity. This means that the potential at point P will essentially be zero, regardless of the value of a. The correct answer is not 0 or KQ0, but rather just KQ. This is because as x becomes larger, the potential at point P will become equal to the potential at infinity, which is set to zero in this problem. Therefore, the potential at point P will be equal to the potential due to the entire rod, which is just KQ. So, as x approaches infinity, the potential at point P will approach KQ.