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Actual vs percieved depth. optics question

by mogley76
Tags: optics, physics
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mogley76
#1
Mar21-11, 07:32 AM
P: 19
1. The problem statement, all variables and given/known data

a man stands by a swimming pool that is completley filled with water. his eyes are 1.8 meters directly above the edge and the pool is 12 meters wide.
when he looks toward the corner on the opposite side of the pool , he estimates the pool to be 2.4 meters deep. if the refractive index of water is 1.33 calculate the actual depth of the pool.


2. Relevant equations

no equations given, but just a statement "the small angle approxmitaion sin theta = tan theta = theta is not appropriate for this situation."




3. The attempt at a solution

i tried using snells law but i get no where as no angles are given and i cant use the small angle approximation . the most i can work out is the critical angle which is sin^-1 (1/1.33) that gives 48.574 deg. but i dont think its gonna help much?
im very stuck
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jambaugh
#2
Mar21-11, 07:42 AM
Sci Advisor
PF Gold
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P: 1,776
Relevant equations?
Attempt at a solution?

To start answer the question: How do we perceive depth?


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