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Weistber
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Hello all,
I got this question off mastering physics and was unable to understand it. I eventually gave up to concentrate on other assignments and asked for the answer. I was unable to come up with more than one answer I thought possible without resorting to trial and error.
Answer: Vx,Vy,Vz = 0,-234,0 m/s
A 6.50 negative microC particle moves through a region of space where an electric field of magnitude 1200 N/C points in the positive x direction, and a magnetic field of magnitude 1.02 T points in the positive z direction.
If the net force acting on the particle is 6.25×10−3 N in the positive x direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane.
Vx = ? Vy =? Vz = ?
Force = electric field * charge
or F=e*q
Force = magnitude of charge * velocity * magnetic field * sin tither
or F=|q|*v*B*sin tither
Force on particle due to Electric Field = E*q
= (1200N/C)(-6.5*10-3 C)
= -7.8*10-3N
Force on charge due to magnetic field = |q|*v*B*sin tither
= (6.5*10-6 C)(1.02T)(v)(sin 90)
= (6.63*10-6)(v)
Fx1 along x-axis = -7.8*103N
I'm sure the force on charge due to magnetic field lies between axis of positive Y and axis of negative X. The force on the particle needs to be perpendicular to the positive z direction of the magnetic field and the velocity of the particle which is one the x-y plane. Since the net force is in the x-direction, it should be along the x-axis. This was also the reasoning that led me to using sin90 when determining the force on the charge due to the magnetic field.
Fx2 along x-axis = (6.63*10-6)(v)
At this point, I thought I understood the problem statement fully. I took the net force from these two vectors I had come up with and separated velocity to LHS and the constants to the right.
Vx= (Net Force x + Fx1) / (Fx2 without velocity term)
= ((6.25×10−3 )+(7.8*103)) / (6.63*10-6)
= 2.12*107 m/s
The value was ridiculously large and I was not surprised it was rejected by mastering physics. I think I have a huge misunderstanding of the concept or method behind this question. Please explain to me how I should go about dealing with a question of this type or point out my mistakes. I do not need a worked out solution, coming up with that myself would probably be better for me.
Thank you
I got this question off mastering physics and was unable to understand it. I eventually gave up to concentrate on other assignments and asked for the answer. I was unable to come up with more than one answer I thought possible without resorting to trial and error.
Answer: Vx,Vy,Vz = 0,-234,0 m/s
Homework Statement
A 6.50 negative microC particle moves through a region of space where an electric field of magnitude 1200 N/C points in the positive x direction, and a magnetic field of magnitude 1.02 T points in the positive z direction.
If the net force acting on the particle is 6.25×10−3 N in the positive x direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane.
Vx = ? Vy =? Vz = ?
Homework Equations
Force = electric field * charge
or F=e*q
Force = magnitude of charge * velocity * magnetic field * sin tither
or F=|q|*v*B*sin tither
The Attempt at a Solution
Force on particle due to Electric Field = E*q
= (1200N/C)(-6.5*10-3 C)
= -7.8*10-3N
Force on charge due to magnetic field = |q|*v*B*sin tither
= (6.5*10-6 C)(1.02T)(v)(sin 90)
= (6.63*10-6)(v)
Fx1 along x-axis = -7.8*103N
I'm sure the force on charge due to magnetic field lies between axis of positive Y and axis of negative X. The force on the particle needs to be perpendicular to the positive z direction of the magnetic field and the velocity of the particle which is one the x-y plane. Since the net force is in the x-direction, it should be along the x-axis. This was also the reasoning that led me to using sin90 when determining the force on the charge due to the magnetic field.
Fx2 along x-axis = (6.63*10-6)(v)
At this point, I thought I understood the problem statement fully. I took the net force from these two vectors I had come up with and separated velocity to LHS and the constants to the right.
Vx= (Net Force x + Fx1) / (Fx2 without velocity term)
= ((6.25×10−3 )+(7.8*103)) / (6.63*10-6)
= 2.12*107 m/s
The value was ridiculously large and I was not surprised it was rejected by mastering physics. I think I have a huge misunderstanding of the concept or method behind this question. Please explain to me how I should go about dealing with a question of this type or point out my mistakes. I do not need a worked out solution, coming up with that myself would probably be better for me.
Thank you
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