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Boyles Law, Graphs 
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#1
May3012, 09:39 AM

P: 168

Hi, what would be the relationship between the product of pressure and volume (pv), against pressure. How would you represent it on a graph?, I have heard that the shape will be a horizontal line. Could someone please show an example or explain it to me?



#2
May3012, 11:02 AM

P: 485

See, for example, this website at NASA. You should feel free to plot the product of pressure and volume against pressure given their demonstration for yourself. You could also plot the product against volume for completeness's sake.



#3
May3012, 11:21 AM

P: 168

Thanks, with the graph volume vs 1/pressure, I should just take the pressure and invert it and then sketch the graph eg. pressure 150kpa = 1/150 = 0.007. Is their any other calculations?



#4
May3012, 11:51 AM

P: 854

Boyles Law, Graphs
[tex]V = \frac{k}{P}[/tex] [tex]PV = k[/tex] From mathematics, this comes out to be a rectangular hyperbola. 


#5
May3012, 12:30 PM

P: 168

So in my example pressure = 150 kPa and Constant = 1530, it will become 1530/150 = 10.2 which is my volume, so its like plotting volume against volume, so my graph is a straight line?, Are you sure this is correct? and also what does the gradient represent, is it temperature?



#6
May3012, 12:49 PM

P: 854

The graph between 1/P and V would simply be a straight line, as it is of the form y=mx ( or V=k/P). This line passes through the origin and has the slope k. 


#7
May3012, 01:10 PM

P: 168

So to get 1/P, it would be V=k/P, right?, and does the gradient represent temperature?



#8
May3012, 01:15 PM

P: 854

[tex]k = PV = RT[/tex] So, k is proportional to temperature, though not exactly equal to temperature. 


#9
May3012, 01:21 PM

P: 168

So k = RT, what does RT represent?



#10
May3012, 10:20 PM

P: 854

R is the universal gas constant, and T is temperature of the gas. 


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