Coefficient of Static Fraction

AI Thread Summary
The coefficient of static friction (μ_s) is often treated as a constant in tables, representing the ratio of the maximum static friction force (F_s) to the normal reaction force (R). While the friction force increases with applied force, μ_s specifically refers to the limiting friction at which motion begins. This means μ_s is effectively the coefficient of limiting friction, indicating the threshold before sliding occurs. Understanding this distinction clarifies why μ_s is presented as a constant despite variations in applied force. The concept is crucial for accurately interpreting friction in practical applications.
poonintoon
Messages
17
Reaction score
0
Please could somebody explain how the coefficient of static friction can be quoted as a constant in tables etc?
\mu_s = F_s/ R
In most cases the reaction force is constant but as I push the box harder the friction force increases.

Is \mu_s actually the coefficient of limiting friction? Or am I totally misunderstanding?
 
Physics news on Phys.org
poonintoon said:
Is \mu_s actually the coefficient of limiting friction?
Yes.
 
  • Like
Likes 1 person
Thread 'Gauss' law seems to imply instantaneous electric field propagation'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (First part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8 and stuck at some statements. It's little bit confused. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. Solution : The surface bound charge on the ##xy## plane is of opposite sign to ##q##, so the force will be...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...

Similar threads

Replies
97
Views
5K
Replies
11
Views
3K
Replies
71
Views
10K
Replies
5
Views
7K
Replies
8
Views
3K
Replies
42
Views
3K
Replies
1
Views
1K
Back
Top