2D advection-dispersion velocity component for fluid flow in a pipe

In summary: I'm betting is not that well-behaved.In summary, the conversation discusses questions about the velocity vector in a pipe, the effect of density differences on point velocities, calculating radial velocity from volumetric rate, and using the chain rule to calculate the derivative of diffusivity. The speaker is seeking reassurance about their understanding and is considering different approaches to solve a problem involving changing diffusivity.
  • #1
maistral
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TL;DR Summary
Assuming the velocity vector for the radial direction is not zero, how do I get it? And other questions.
Pardon if the answers to my questions are obvious, because as usual I am trying to decipher everything on my own (as the material has not been taught to us quite well; then again it's graduate school). I just need someone to reassure me that I am understanding this correctly.

Say for example I have a pipe where the 2D advection dispersion equation applies on the flowing fluid (assume tangential/angular gradients are negligible), I will have the quantity ur for the velocity along the radial direction and uz for the axial direction.

1. Am I correct to assume that the 'true' velocity would be the resultant of these two? ergo, u = √(ur2 + uz2), where u is the 'true entrance velocity' of the fluid in the pipe (and that u = uz because it is a general assumption that ur is zero since this is a pipe, and that radial velocities are near inexistent?)

2. Assuming that there are density differences (due to temperature), obviously there will be differences to the point velocities as velocity = volumetric rate / area; and that volumetric rate and density are inversely related. If say for example, uz is zero, I am assuming that ∂uz/∂z is not necessarily zero due to these density differences in different points along the fluid region (change in densities will cause change in volumetric rate). Is this correct?

3. Also, if I want to calculate ur from the point volumetric rate, then it's ur = volumetric rate / radial area, and I am assuming the radial area = 2πrL?

4. I know this is so undergraduate and stupid (pardon me, lol). I have a quantity Di for diffusivity coefficient which is a function of flow rate Fi of two components, temperature T, and pressure P, and that Di returns a vector containing the diffusivities of two components. If I intend to calculate ∂Di/∂z, I can use chain rule. I am assuming this is correct, lol.

So if I intend to calculate ∂Di/∂z, I can calculate (∂Di/∂Fi) (∂Fi/∂z), which would probably be inefficient since I have to keep calling the diffusion function one by one to calculate the derivative for the first component and the second component. I thought of just chaining it to ∂Di/∂T such that (∂Di/∂T) (∂T/∂z) so that the returning vector would automatically be derivatives of the diffusion coefficient of each component. I am actually thinking this is allowable since I did not exactly break any mathematical law, lol. It's just that I want to make sure because manipulating my program with respect to T is so taxing.

Thank you so much in advance.
 
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  • #2
maistral said:
Summary: Assuming the velocity vector for the radial direction is not zero, how do I get it? And other questions.

Pardon if the answers to my questions are obvious, because as usual I am trying to decipher everything on my own (as the material has not been taught to us quite well; then again it's graduate school). I just need someone to reassure me that I am understanding this correctly.

Say for example I have a pipe where the 2D advection dispersion equation applies on the flowing fluid (assume tangential/angular gradients are negligible), I will have the quantity ur for the velocity along the radial direction and uz for the axial direction.

1. Am I correct to assume that the 'true' velocity would be the resultant of these two? ergo, u = √(ur2 + uz2), where u is the 'true entrance velocity' of the fluid in the pipe (and that u = uz because it is a general assumption that ur is zero since this is a pipe, and that radial velocities are near inexistent?)
If you are talking about flow in the entrance region of the pipe, then, by continuity, the radial velocity is non-zero.
2. Assuming that there are density differences (due to temperature), obviously there will be differences to the point velocities as velocity = volumetric rate / area; and that volumetric rate and density are inversely related. If say for example, uz is zero, I am assuming that ∂uz/∂z is not necessarily zero due to these density differences in different points along the fluid region (change in densities will cause change in volumetric rate). Is this correct?
I don't understand this question.
3. Also, if I want to calculate ur from the point volumetric rate, then it's ur = volumetric rate / radial area, and I am assuming the radial area = 2πrL?[/quoe]
I don't understand this question either.
4. I know this is so undergraduate and stupid (pardon me, lol). I have a quantity Di for diffusivity coefficient which is a function of flow rate Fi of two components, temperature T, and pressure P, and that Di returns a vector containing the diffusivities of two components. If I intend to calculate ∂Di/∂z, I can use chain rule. I am assuming this is correct, lol.
You're saying that diffusivity is a function of concentration, temperature, and pressure, and these parameters are changing? If this is what you are asking, then, yes, you can use the chain rule.
So if I intend to calculate ∂Di/∂z, I can calculate (∂Di/∂Fi) (∂Fi/∂z), which would probably be inefficient since I have to keep calling the diffusion function one by one to calculate the derivative for the first component and the second component. I thought of just chaining it to ∂Di/∂T such that (∂Di/∂T) (∂T/∂z) so that the returning vector would automatically be derivatives of the diffusion coefficient of each component. I am actually thinking this is allowable since I did not exactly break any mathematical law, lol. It's just that I want to make sure because manipulating my program with respect to T is so taxing.

Thank you so much in advance.
You are trying to solve a problem in which diffusivity of a species is changing with spatial position numerically? Why are you not keeping the diffusivity inside the spatial gradient along with the concentration derivative? This is a better way to do the spatial discretization. And you won't have to evaluate partial derivatives of the diffusivity with respect to temperature, pressure, and composition.
 
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  • #3
Chestermiller said:
If you are talking about flow in the entrance region of the pipe, then, by continuity, the radial velocity is non-zero.

May I ask how to solve for this? Say I have an entrance velocity u of 10 in SI units. How do I know who is uz and who is ur?

Chestermiller said:
I don't understand this question.

I was going to express the point velocity uz or ur in terms of volumetric rate. But since volumetric rate changes with temperature, and temperature changes with position (due to heat exchange or generation), then volumetric rate must change with position, then in turn, point velocity changing with respect to position.

If I initially assumed that my ur is insignificant (zero), it is still possible to get a value for ∂ur/∂r because of this, yes?

Chestermiller said:
I don't understand this question either.

If I have a volumetric rate of 10 in SI, and assuming the volumetric rate changes because of the position (same issue I had with the previous question), I wanted to express ur as a function of the point volumetric rate. Which area do I use, 2πrL?

Chestermiller said:
You are trying to solve a problem in which diffusivity of a species is changing with spatial position numerically? Why are you not keeping the diffusivity inside the spatial gradient along with the concentration derivative? This is a better way to do the spatial discretization. And you won't have to evaluate partial derivatives of the diffusivity with respect to temperature, pressure, and composition.

I was thinking about this long and hard, to the point that roommates were reprimanding me that I looked like someone constipating from too much thinking about this, hahaha. I just got on instead of overthinking and expanded the flux derivatives. I should have finite-differenced fluxes instead. Lol, thanks for answering a question that boggled me for a week. Next time I would remember this, thank you very very much.Also, I have this last... particular question. At the entrance of my pipe, temperature, total volumetric rate (say, 5 L/s), and pressure is constant. Say I have 10 nodes assigned at the pipe entrance. I have a total molar rate entering the pipe. (say 3 mol/s). I wanted the concentration at the entrance to solve my diffusion equation. What should I put at the top nodes?

  • Do I divide the 5L/s by 10, since there are 10 nodes; then I would divide the 3mol/s by 10 as well, since there are 10 nodes; then I will get the concentration from the quotient of the two (3÷5 mol/L to all ten nodes)?
  • Or do I hold the 5 L/s constant to all of the nodes, then chop the 3 mol/s to each node (0.3÷5 mol/L to all ten nodes)?
  • Or do I hold the molar rate constant, then divide the 5L/s to all 10 nodes (3÷0.5 mol/L to all ten nodes)?
  • Or do I not divide anything by anything (3÷5 mol/L to all ten nodes)?
If it is either the first or the last, please do tell me if I have to divide the volumetric rate or not. I'm trying to understand the concepts of things.

Thank you, very very much.
 
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  • #4
maistral said:
May I ask how to solve for this? Say I have an entrance velocity u of 10 in SI units. How do I know who is uz and who is ur?
I don't fully understand what you are asking here, but, if you are interested in getting a start in your thinking about entrance flows, study the Blasius solution to flow past a flat plate, which handles velocity components in both the x and y directions, even though the main component of velocity is in the x direction. Entrance flow in a pipe begins like the Blasius solution, since the boundary layer is thin compared to the pipe radius, and thus, the curvature can be neglected.
I was going to express the point velocity uz or ur in terms of volumetric rate. But since volumetric rate changes with temperature, and temperature changes with position (due to heat exchange or generation), then volumetric rate must change with position, then in turn, point velocity changing with respect to position.

If I initially assumed that my ur is insignificant (zero), it is still possible to get a value for ∂ur/∂r because of this, yes?
I don't know what you are trying to do here. Sorry..

If I have a volumetric rate of 10 in SI, and assuming the volumetric rate changes because of the position (same issue I had with the previous question), I wanted to express ur as a function of the point volumetric rate. Which area do I use, 2πrL?
Again, I'm clueless about what you are getting at.

Also, I have this last... particular question. At the entrance of my pipe, temperature, total volumetric rate (say, 5 L/s), and pressure is constant. Say I have 10 nodes assigned at the pipe entrance. I have a total molar rate entering the pipe. (say 3 mol/s). I wanted the concentration at the entrance to solve my diffusion equation. What should I put at the top nodes?

  • Do I divide the 5L/s by 10, since there are 10 nodes; then I would divide the 3mol/s by 10 as well, since there are 10 nodes; then I will get the concentration from the quotient of the two (3÷5 mol/L to all ten nodes)?
  • Or do I hold the 5 L/s constant to all of the nodes, then chop the 3 mol/s to each node (0.3÷5 mol/L to all ten nodes)?
  • Or do I hold the molar rate constant, then divide the 5L/s to all 10 nodes (3÷0.5 mol/L to all ten nodes)?
  • Or do I not divide anything by anything (3÷5 mol/L to all ten nodes)?
If it is either the first or the last, please do tell me if I have to divide the volumetric rate or not. I'm trying to understand the concepts of things.
If I understand you correctly, I would choose the first.
 

1. What is the 2D advection-dispersion velocity component for fluid flow in a pipe?

The 2D advection-dispersion velocity component for fluid flow in a pipe refers to the velocity of a fluid as it moves through a pipe in two dimensions, taking into account both advection (the movement of the fluid due to bulk flow) and dispersion (the spreading of the fluid due to diffusion and other factors).

2. How is the 2D advection-dispersion velocity component calculated?

The 2D advection-dispersion velocity component is calculated using mathematical equations that take into account the fluid properties, pipe dimensions, and flow conditions. These equations are based on the principles of fluid mechanics and mass transport.

3. What factors affect the 2D advection-dispersion velocity component?

The 2D advection-dispersion velocity component can be affected by various factors such as the fluid viscosity, pipe diameter, flow rate, and the presence of obstacles or irregularities in the pipe. Other factors that may influence the velocity component include temperature, pressure, and fluid properties such as density and viscosity.

4. Why is the 2D advection-dispersion velocity component important in fluid flow analysis?

The 2D advection-dispersion velocity component is important in fluid flow analysis because it helps to predict the movement and behavior of fluids in a pipe. By understanding the velocity component, scientists and engineers can better design and optimize systems for fluid transport, such as in industrial processes or water distribution systems.

5. How can the 2D advection-dispersion velocity component be measured or tested?

The 2D advection-dispersion velocity component can be measured or tested through various methods such as flow visualization techniques, tracer studies, or using specialized instruments such as flow meters or pressure sensors. These methods can provide valuable data for validating mathematical models and improving our understanding of fluid flow in pipes.

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