A 2.00 kg rim with a radius of 20.0 cm is sitting on an 8.00 kg wedge

In summary, the conversation discusses the minimum coefficient of static friction, minimum force, and maximum force required for a 2.00 kg rim with a radius of 20.0 cm to roll without slipping on an 8.00 kg wedge at a 30 degree angle with a kinetic coefficient of friction of 0.20 between the wedge and the floor. It also mentions the relevant equations needed for solving these problems. However, the image provided is not viewable and more information or an attempt is required according to forum rules.
  • #1
Alabaster1327
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Homework Statement
A 2.00 kg rim with a radius of 20.0 cm is setting on an 8.00 kg wedge of angle 30 degrees. The kinetic coefficient of kinetic friction between the wedge and the floor is 0.20

A) With F = 0.00 N, find the minimum coefficient of static friction between the rim and the wedge required for rolling without slipping.

B) Find the minimum force required to keep the rim from rolling downward.

C) Find the maximum force required to get the rim rolling upwards at a constant speed.
Relevant Equations
.
https://www.physicsforums.com/attachments/264405
 
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  • #2
Alabaster1327 said:
Homework Statement:: A 2.00 kg rim with a radius of 20.0 cm is setting on an 8.00 kg wedge of angle 30 degrees. The kinetic coefficient of kinetic friction between the wedge and the floor is 0.20

A) With F = 0.00 N, find the minimum coefficient of static friction between the rim and the wedge required for rolling without slipping.

B) Find the minimum force required to keep the rim from rolling downward.

C) Find the maximum force required to get the rim rolling upwards at a constant speed.
Relevant Equations:: .

https://www.physicsforums.com/attachments/264405
Rim? Do you mean a disc? Ring?
Your image is not viewable. Seems to require authority.
Per forum rules, you must show some attempt.
 

1. What is the mass of the system?

The total mass of the system is 10.00 kg, which is the sum of the rim's mass (2.00 kg) and the wedge's mass (8.00 kg).

2. What is the acceleration of the system?

The acceleration of the system depends on the forces acting on it. If there is no external force, the system will remain at rest or in a state of constant velocity. If there is a net external force, the system will accelerate in the direction of the force according to Newton's second law, F=ma.

3. How does the radius of the rim affect the system?

The radius of the rim affects the moment of inertia of the system, which is a measure of an object's resistance to rotational motion. A larger radius will result in a larger moment of inertia and thus require more torque to rotate the system.

4. What is the relationship between the rim and the wedge?

The rim and the wedge are in contact with each other, and thus experience a normal force and a frictional force. The normal force is perpendicular to the contact surface and prevents the rim from falling through the wedge. The frictional force is parallel to the contact surface and prevents the rim from sliding down the wedge.

5. What would happen if the mass of the rim is increased?

If the mass of the rim is increased, the moment of inertia of the system will also increase. This will require more torque to rotate the system and may result in a slower acceleration or a larger normal force and frictional force between the rim and the wedge.

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