- #1
hoseA
- 61
- 0
Angular Acceleration/ Find angle in period -- PLEASE help!
I'm having trouble with part "B" please help.
A.)A dentist's drill starts from rest. After 4.95 s
of constant angular acceleration, it turns at a
rate of 28600 rev/min.
Find the drill's angular acceleration. An-
swer in units of rad/s^2.
B.)Find the angle through which the drill rotates
during this period. Answer in units of rad.
A.) [(28600*2pi)/60]/4.95 = 605.047 rad/s^2
B.) [(28600*2pi)/60] * 4.95 = 14825 rad. (but this is not the right answer?)
Am I using the wrong formula? Any help appreciated.
I'm having trouble with part "B" please help.
A.)A dentist's drill starts from rest. After 4.95 s
of constant angular acceleration, it turns at a
rate of 28600 rev/min.
Find the drill's angular acceleration. An-
swer in units of rad/s^2.
B.)Find the angle through which the drill rotates
during this period. Answer in units of rad.
A.) [(28600*2pi)/60]/4.95 = 605.047 rad/s^2
B.) [(28600*2pi)/60] * 4.95 = 14825 rad. (but this is not the right answer?)
Am I using the wrong formula? Any help appreciated.