Angular Acceleration Homework: 1014.65°, 17.97 rad/s

In summary: The given information does not seem to be related to the stated problem about a rotating wheel. Please provide more context.
  • #1
dr2112
9
0

Homework Statement


wheel rotates w constant acceleration 3.65rad/s2
angular speed is 3.00 rad/s at t=0
a)what angle does wheel rotate between t=0 and t=3.67s?
b)what is angular speed of wheel at 4.1s?


Homework Equations


wt+1/2alphat
(3.00rad/s)(3.67t)+1/2(3.65rad/s2)(3.67)2=17.70rad
17.70rad*360degrees/628rad=1014.65degrees

w=w0+alpha t
3.00rad/s+3.65rad/s2(4.1s)=17.97rad/s

The Attempt at a Solution


a=1014.65 degrees
b=17.97rad/s

 
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  • #2
Hi dr2112,

dr2112 said:

Homework Statement


wheel rotates w constant acceleration 3.65rad/s2
angular speed is 3.00 rad/s at t=0
a)what angle does wheel rotate between t=0 and t=3.67s?
b)what is angular speed of wheel at 4.1s?


Homework Equations


wt+1/2alphat
(3.00rad/s)(3.67t)+1/2(3.65rad/s2)(3.67)2=17.70rad

I don't believe this is correct. The final t needs to be squared:

[tex]
\Delta\theta = \omega_0 t + \frac{1}{2}\alpha t^2
[/tex]
 
  • #3
alphysicist said:
Hi dr2112,



I don't believe this is correct. The final t needs to be squared:

[tex]
\Delta\theta = \omega_0 t + \frac{1}{2}\alpha t^2
[/tex]

Ok how is 1.60 m/s^2 for tangential and 8.61 m/s^2 for total acceleration?
 
  • #4
dr2112 said:
Ok how is 1.60 m/s^2 for tangential and 8.61 m/s^2 for total acceleration?

Is this for a different problem, or is there more to the problem in your first post?
 

Related to Angular Acceleration Homework: 1014.65°, 17.97 rad/s

1. How do you calculate angular acceleration?

Angular acceleration is calculated by dividing the change in angular velocity by the change in time. The formula for angular acceleration is Δω/Δt. In this case, the angular velocity is given as 17.97 rad/s and the change in time is 1014.65°. Therefore, the angular acceleration would be 17.97 rad/s divided by 1014.65°, which is approximately 0.0177 rad/s².

2. What is the unit of measurement for angular acceleration?

The unit of measurement for angular acceleration is radians per second squared (rad/s²). This unit is derived from the formula for angular acceleration, which divides the change in angular velocity (measured in radians per second) by the change in time (measured in seconds).

3. How does angular acceleration differ from linear acceleration?

Angular acceleration and linear acceleration are different because they measure different types of motion. Angular acceleration measures the rate at which an object's angular velocity (how fast it is rotating) changes over time, while linear acceleration measures the rate at which an object's linear velocity (how fast it is moving in a straight line) changes over time.

4. Can angular acceleration be negative?

Yes, angular acceleration can be negative. A negative angular acceleration means that the object is slowing down its rotation, while a positive angular acceleration means that the object is speeding up its rotation. In this case, the angular acceleration is given as 17.97 rad/s, which is a positive value, indicating that the object is accelerating in a clockwise direction.

5. How is angular acceleration related to angular velocity and tangential acceleration?

Angular acceleration is related to angular velocity and tangential acceleration through the formula a = rα, where "a" is tangential acceleration, "r" is the radius of the circular motion, and "α" is the angular acceleration. This formula shows that tangential acceleration is directly proportional to the radius and angular acceleration. It also means that an increase in angular acceleration will result in an increase in tangential acceleration, and vice versa.

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