Angular acceleration of tires on a car

In summary, the conversation discusses the problem of finding the angular acceleration of a car's tires given its linear acceleration, elapsed time, and tire radius. A battle plan is proposed, and a solution is attempted using the equations for linear displacement, speed, and acceleration in terms of angular displacement, speed, and acceleration. However, the correct answer is found to be 0.619 rad/s², not 0.198198198 rad/s² as originally calculated.
  • #1
Spartan301
20
0

Homework Statement


You accelerate your car from rest at a constant rate down a straight road and reach 22.0 m/s in 111s. The tires on your car have radius 0.320 m. Assuming the tires rotate in a counterclockwise direction, what is the angular acceleration of the tires?

Homework Equations


Givens:
Initial velocity: 0
Final velocity: 22.0 m/s
Elapsed time: 111s
Tire radius: 0.320 m

Objective: Find the angular acceleration of the tires.

Battle Plan:
Find the linear displacement from the average acceleration and the elapsed time.
(vf² = vi² + 2aΔx)
Find the circumference of the tires from the radius, and divide the linear displacement by the circumference to find the number of rotations in that length.
Use ΔΘ = Θf-Θi, having multiplied the number of full rotations by 2π.
Divide the angular displacement by the elapsed time to find angular velocity.
Divide the change in angular velocity by the elapsed time to find angular acceleration

The Attempt at a Solution


Outcome:
a = 0.198198198
vf² = vi² + 2aΔx
vf² - vi² = 2aΔx
(vf² - vi²)/2a = Δx
22 m²/s² / 2(0.198198198 m/s^2) = Δx
22 m²/s² / 0.396396396 m/s^2
Linear displacement: 55.5 m

Radius: 0.320 m
Circumference = 2π(0.320m) = 2.010619298 m

55.5 m/ 2.010619298 m = 27.60343544 rotations.

27.60343544 rotations x 2π = 173.4375 radians

173.4375 radians/ 111s = 1.5625 rad/s

1.5625 rad/s / 111s = 0.014076577 rad/s²

They say the answer is supposed to be 0.619 rad/s²

Thank you for your help. Let me know if I can return the favor.

-Tom
 
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  • #2
Hi Tom! :smile:

linear displacement = r x angular displacement: s = rθ

linear speed = r x angular speed: v = rω

linear acceleration = r x angular acceleration: a = rα :wink:
 
  • #3
Thanks for replying Tim.

tiny-tim said:
Hi Tom! :smile:

linear displacement = r x angular displacement: s = rθ

linear speed = r x angular speed: v = rω

linear acceleration = r x angular acceleration: a = rα :wink:

I do not understand.
 
  • #4
Spartan301 said:
The tires on your car have radius 0.320 m … what is the angular acceleration of the tires?

a = 0.198198198

They say the answer is supposed to be 0.619 rad/s²

a = rα :wink:
 
  • #5
Ooooh! Now I understand! Good job! Thank you!
 

1. What is angular acceleration?

Angular acceleration is the rate of change of angular velocity, which is the measure of how quickly an object rotates around a fixed axis.

2. How is angular acceleration different from linear acceleration?

Angular acceleration is a measure of how quickly an object changes its rotational speed, while linear acceleration is a measure of how quickly an object changes its linear speed in a straight line.

3. How does angular acceleration affect a car's tires?

Angular acceleration affects a car's tires by causing them to rotate at a faster or slower rate, depending on the direction and magnitude of the acceleration. This can impact the car's overall speed and handling.

4. What factors can affect the angular acceleration of a car's tires?

The amount of torque applied to the tires, the mass and distribution of weight in the car, and the friction between the tires and the road are all factors that can affect the angular acceleration of a car's tires.

5. How is angular acceleration measured on a car?

Angular acceleration on a car can be measured using sensors that track the rotation of the tires, such as a gyroscope or an accelerometer. These sensors can provide data on the rate of change of the tires' rotational speed, which can then be used to calculate the angular acceleration.

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