- #1
dustbin
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Homework Statement
Assume that [tex] \{ a_n\}\rightarrow 0 [/tex]. Use the definition of limit to prove that [tex] \{ a_n^2\} \rightarrow 0[/tex].
Homework Equations
Definition of limit. For all ε>0 there exists N s.t. n>N implies |a_n - L|<ε.
The Attempt at a Solution
I know why this is true... if the sequence goes to zero then a_n<1. Therefore [tex] a_n^2 < a_n < 1 [/tex]. Then [tex] a_n^2 [/tex] is bounded above by a_n and below by zero, so it also converges. Is this as simple as:
Assume that given an ε>0 we choose N s.t. for all n>N implies |a_n - 0|<sqrt(ε). Then since [tex] a_n > a_n^2[/tex] we have [tex] |a_n^2|<\varepsilon [/tex]. Where L=0.
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