- #1
Bashyboy
- 1,421
- 5
Would this would the proper function, as described in the title of this thread, [itex]A = 1/2 x^2 \cos \frac{\theta}{2}[/itex]?
And suppose that the side x and the angle were changing with time, would the derivative, with respect to time, be [itex]\frac{dA}{dt} = x \cos \frac{\theta}{2} - 1/4 x^2 \sin \frac{\theta}{2}[/itex]?
Did I properly derive these?
And suppose that the side x and the angle were changing with time, would the derivative, with respect to time, be [itex]\frac{dA}{dt} = x \cos \frac{\theta}{2} - 1/4 x^2 \sin \frac{\theta}{2}[/itex]?
Did I properly derive these?