Asteroid Binding Energy: E=mv^2?

In summary, asteroid binding energy refers to the energy required to keep an asteroid in orbit around a larger object, such as a planet or star. It is calculated using the formula E=mv^2, where m is the mass of the asteroid and v is its velocity. This energy is important for understanding the stability of asteroid orbits and predicting potential collisions with other objects in the solar system.
  • #1
Tris Fray Potter
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If the binding energy in nuclear physics is e=mc^2, then would the binding energy of a larger object be:
e=mv^2
where v=the velocity of the asteroid?
 
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  • #2
In the binding energy equation the m is the mass deficit ... does the concept of mass deficit apply to the asteroid?
In the asteroid equation, v is the speed of the asteroid; in the binding energy, the speed "c" appears in the same place... does that mean that the nucleus is moving at the speed of light?
In short: no. You cannot do physics by analogy.
 
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  • #3
Simon Bridge said:
In the binding energy equation the m is the mass deficit ... does the concept of mass deficit apply to the asteroid?
In the binding energy, the speed "c" appears ... does that mean that the nucleus is moving at the speed of light?
In short: no. You cannot do physics by analogy.
Okay. Thank-you. Do you know how I would be able to find the binding energy of the asteroid?
 
  • #4
Tris Fray Potter said:
Okay. Thank-you. Do you know how I would be able to find the binding energy of the asteroid?

There are several types of binding energy. Which one are you looking for? Gravitational? Nuclear? Chemical?
 
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  • #5
Drakkith said:
There are several types of binding energy. Which one are you looking for? Gravitational? Nuclear? Chemical?
I think gravitational. I need to know if a bomb would explode an asteroid or not, and I was going to do a comparison on the energy of the bomb (which I've already figured out), to the binding energy of the asteroid.
 
  • #8
Note that the binding energy of an asteroid also contributes to its mass via E=mc2 as every energy in the rest frame does, but the contribution is completely negligible.
 
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  • #9
... if the idea is to destroy the asteroid before it arrives at some target, detonating it won't remove it's kinetic energy (though distributing the bits over a big volume can reduce the amount of mass that strikes the target. Phil Plait has an artical about it.
 
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Related to Asteroid Binding Energy: E=mv^2?

1. What is asteroid binding energy?

Asteroid binding energy refers to the amount of energy required to break apart or disrupt an asteroid. It is a measure of the asteroid's stability and structural integrity.

2. How is the binding energy of an asteroid calculated?

The binding energy of an asteroid can be calculated using the formula E=mv^2, where E is the binding energy, m is the mass of the asteroid, and v is its velocity.

3. What factors affect the binding energy of an asteroid?

The binding energy of an asteroid is influenced by its mass, velocity, and composition. A larger asteroid with a higher velocity and denser composition will have a higher binding energy.

4. Why is the binding energy of an asteroid important?

The binding energy of an asteroid is important because it can affect its potential impact on Earth. A higher binding energy means that the asteroid is more stable and less likely to break apart, potentially causing more damage upon impact.

5. How is the binding energy of an asteroid relevant to space exploration?

The binding energy of an asteroid is relevant to space exploration because it can impact the difficulty and feasibility of capturing and redirecting asteroids for mining or other purposes. A higher binding energy would require more energy and resources to manipulate the asteroid's trajectory.

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