- #1
ScreamingIntoTheVoid
Homework Statement
The figure shows Atwood's machine, in which two containers are connected by a cord (of negligible mass) passing over a frictionless pulley (also of negligible mass). At time t = 0 container 1 has mass 1.3 kg and container 2 has mass 2.7 kg, but container 1 is losing mass (through a leak) at the constant rate of 0.24 kg/s. At what rate is the acceleration magnitude of the containers changing at (a)t = 0 and (b)t = 3 s?
Homework Equations
f=ma[/B]
The Attempt at a Solution
**NOTE, a is not 0**
T= m1g - m2g = 26.46-12.74= 13.72
4a=13.72 (**4 is the mass of the entire system**) a= 3.43 m/s^2
Try 1:
d/dt 3.43 + 0.24t --> 0.24 m/s^3 for both a and b (which is obviously wrong)
Try 2: *Lets find a at t=3*
1.3 - 0.24(3)= 0.58
T= 26.46 - 5.684= 20.776
(3.28)a = 20.776 --> a= 6.331097561
(6.331097561m/s^2-3.43m/s^2)/3s = 0.9670325203 m/s^3 (which was also wrong)
Help please? I'm not looking for answers, I just want to know how to do this. Thank you in advance!