- #1
david12
- 5
- 0
Here is my question guys ...i guess you can help me out .
1.A basketball player achieves a hang time of 1.33 second in dunking the ball.the acceleration of gravity is 9.8m/s^2.what is vertical hight will he attain.answer in m.
here is what i did.
Y=Y(inital) + v(inital)t + 1/2 gt^2
which is Y = 0.5(9.8)(1.33^2)
=8.6676 m
I don't know what i did wrong but my answer is wrong.
thank you.
1.A basketball player achieves a hang time of 1.33 second in dunking the ball.the acceleration of gravity is 9.8m/s^2.what is vertical hight will he attain.answer in m.
here is what i did.
Y=Y(inital) + v(inital)t + 1/2 gt^2
which is Y = 0.5(9.8)(1.33^2)
=8.6676 m
I don't know what i did wrong but my answer is wrong.
thank you.