No, @reanamate has rω2. Changing "centripetal force" to "centripetal acceleration" everywhere fixes all the issues.kuruman said:What you have is Fc = v2.
Having misread the parentheses, I stand corrected.haruspex said:No, @reanamate has rω2.
The speed of the spinning disk does not necessarily affect the distance the bug flies off. Other factors such as the size and type of bug, the surface of the disk, and the angle at which the bug is launched also play a role.
No, the distance the bug flies off may vary each time the experiment is repeated due to factors such as the initial position of the bug, the speed and direction of the spinning disk, and any external forces acting on the bug.
There is no simple formula to calculate the distance the bug flies off, as it depends on multiple variables. However, with precise measurements and data, a mathematical model can be created to estimate the distance.
The relationship between the distance the bug flies off and the rotational speed of the disk is not linear. As the rotational speed increases, the bug may experience greater centrifugal force and be launched at a higher velocity, resulting in a longer distance. However, at a certain point, the bug may not be able to hold onto the disk and will fly off at a shorter distance.
The surface of the spinning disk can affect the distance the bug flies off in several ways. A rougher surface may provide more friction and prevent the bug from slipping off, resulting in a shorter distance. A smoother surface may reduce friction and allow the bug to travel a longer distance. Additionally, the shape and texture of the surface can impact the trajectory of the bug, affecting the distance it travels.