Calculate Stress & Strain from Length, Diameter & Load

In summary, to calculate the stress (N/mm2) and strain (%) of a material with a length of 50mm, diameter of 12mm, load of 11.5 kN, and extension of 0.025 mm, you will need to have a clear understanding of the definition of stress and the concept of strain being proportional to length. The stress can be determined by dividing the load by the cross-sectional area of the material, while the strain can be calculated by dividing the extension by the original length. It is important to have a clear understanding of these concepts before attempting the specific problem.
  • #1
Chuck Finley
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No template because submitted to wrong forum
Unsure how to calculate in order to get the stress (N/mm2) and strain (%) if:
a material has a length of 50mm
diameter of 12mm
Load: 11.5 kN
Extension 0.025 mm

Help on how to work this out would be very appreciated :)
 
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  • #2
Note the forum guidelines insist you show some attempt but let me see if I can get you started.

You need the mental picture of, I think in this case, tensile stress and strain. It appears as if the material is cylinderical so has a circular cross sectional area. Note that the stress units are force per area. Double check your textbook on the definition of stress. [If you haven't a clear idea of its definition you should not have started this problem yet.]

Secondly the cylinder has a length (50mm) and that is extended by the strain produced by the force (the extension amount) and so % strain should be an obvious calculation. Note that tensile stress extends along the entire length of a wire or rod so doubling the rod is equivalent to stacking two rods so doubling the length should double the strain for the same material and stress. Strain is proportional to the length in other words so it makes sense to express it as a proportion change.
[Again this is something you should understand before attempting the specific problem.]
 

1. How do I calculate stress from length, diameter, and load?

To calculate stress, you can use the formula stress = force/area. In this case, force would be the load applied and area would be calculated using the diameter. So, the formula would be stress = load/(π x (diameter/2)^2).

2. What is the difference between stress and strain?

Stress is a measure of the force applied to a material per unit area, while strain is a measure of the deformation or change in shape of a material due to the applied force. In simpler terms, stress is the force, and strain is the effect of that force.

3. Can I use any unit of measurement for length, diameter, and load?

Yes, you can use any unit of measurement as long as they are all consistent. For example, if you use inches for length and diameter, make sure to use pounds for the load. Also, make sure to convert all units to the same system if necessary.

4. Is there a limit to the stress a material can handle?

Yes, every material has a maximum stress it can handle before it deforms or breaks. This is known as the material's ultimate tensile strength. It is important to know this limit when designing structures or machines to ensure they can withstand the expected stress.

5. How can I use stress and strain calculations in real-life applications?

Stress and strain calculations are essential in engineering and manufacturing industries. They are used to design and test various structures, such as buildings, bridges, and aircraft, to ensure they can withstand expected loads without failure. These calculations are also used in material selection and quality control processes.

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