Calculating Antimatter Portion in Protons

[papanatas]

Hi! I am asked to calculete the portion of antimatter present in protons. I am sayed that this portion is given by:
r=(3R-1)/(3-R), where R is R=σ(antineutrino)/σ(neutrino). Another definition of r is r=∫x*Q'(x)dx/∫x*Q(x)dx, where Q(x) are partonic densities Q(x)=d(x)+u(x) (d is down quark and u up quark). Q'=d'(x)+u'(x) (d' antidown and u' antiup). x is Bjorken variable x.

After doing this, I am asked to say if this answer would be correct if we included density of quarks s and s' (strong, antistrong), and to tell how this density would manifest in total cross section.

Can you guys help me or give me some bibliography? I am sorry if I haven't made myself clear, English is not my mother language...

 

[LightHero]

The answer to your first question is yes, the calculation of the portion of antimatter present in protons would be correct if we included the densities of quarks s and s'. The quark densities manifest in total cross section by influencing the total number of interactions between incoming particles and targets. The more quarks present, the more interactions occur and thus higher cross section. For example, collisions between quarks and gluons are more likely when the quark density is higher. This increases the total cross section of the process.