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1. In the figure the square loop of wire has sides of length 2 cm. A magnetic field points out of the page; its magnitude is given by
B = 4.0 t^2y
where B is in teslas, t is in seconds and y is in meters. Determine the emf around the square at t = 1.50 s.
[URL]http://homework.phyast.pitt.edu/res/sc/gblanpied/courses/usclib/hrw8/hrwpictures/31-43.jpg[/URL]2. emf = -Change in Flux
B = 4*t^2*y
Integrated the equation with respect to y over an interval of 0 to 0.02 meters (length of y), multiplied result by 0.02 (length of x). Final result was 0.000016*t^2, which should also be the flux.
Flux = 0.000016*t^2
Derived the equation, and got dFlux = 0.000032*t dt.
Inserted 1.5 into t and got 0.000048.
emf = -0.000048 V.
Answer isn't correct.
B = 4.0 t^2y
where B is in teslas, t is in seconds and y is in meters. Determine the emf around the square at t = 1.50 s.
[URL]http://homework.phyast.pitt.edu/res/sc/gblanpied/courses/usclib/hrw8/hrwpictures/31-43.jpg[/URL]2. emf = -Change in Flux
The Attempt at a Solution
B = 4*t^2*y
Integrated the equation with respect to y over an interval of 0 to 0.02 meters (length of y), multiplied result by 0.02 (length of x). Final result was 0.000016*t^2, which should also be the flux.
Flux = 0.000016*t^2
Derived the equation, and got dFlux = 0.000032*t dt.
Inserted 1.5 into t and got 0.000048.
emf = -0.000048 V.
Answer isn't correct.
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