- #1
free-node-5
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Homework Statement
How much energy is required to change a 46.0 g ice cube from ice at -10.0°C to steam at 116°C?
Homework Equations
specific heat
c = Q/(m(Tf-Ti))
Q = cm(Tf-Ti)
latent heat
Q = mL
The Attempt at a Solution
2.05*10*46+4.1813*100*46+2.080*16*46 + 2260*.046+334*.046
= 21827.184J
(please only speak in metrics or you'll lose me)
can anyone help me figure this out?
It's very crucial that I understand this process.
thanks