Calculating Potential Difference in an Electric Field with Given Field Equation

In summary, the electric field is given by Ex = 2.2x + 5x2kNC-1 and the potential difference between two points on the x-axis at x = -2.0 m and x = 2.0 m is -27V due to the negative sign in the formula for electric potential.
  • #1
chopnhack
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Homework Statement


An electric field is given by Ex = 2.2x + 5x2kNC-1. Find the potential difference between two points on the x-axis at x = -2.0 m and x = 2.0 m

Homework Equations


∫5x2+2.2x from -2 to 2

The Attempt at a Solution


I got the answer of 27V.

Solution said - negative 27V

Can someone please explain?
Thanks
 
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  • #2
chopnhack said:
∫5x2+2.2x from -2 to 2
Remember there is a negative sign in front of this integral since
$$\mathbf{E}=-\nabla V$$.
 
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  • #3
##\Delta V = -\int_{-2}^2{\vec{E} \cdot d\vec{s}}##
You left out the negative sign.
 
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  • #4
NFuller said:
Remember there is a negative sign in front of this integral since
$$\mathbf{E}=-\nabla V$$.
yes, sadly I recall it now...

giphy.gif
 
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  • #5
I was so happy to have found the proper way of handling it, I didn't recall the formula!
Thanks all.
 

Related to Calculating Potential Difference in an Electric Field with Given Field Equation

What is an electric field?

An electric field is a physical quantity that describes the strength and direction of the force exerted by electric charges. It is represented by lines of force that point in the direction a positive test charge would move when placed in the field.

How is an electric field created?

An electric field is created by the presence of electric charges. Positive charges create electric fields that point away from them, while negative charges create fields that point towards them. These fields can also be created by changing magnetic fields, according to Maxwell's equations.

What is electric potential?

Electric potential is a measure of the electric potential energy per unit charge at a specific point in an electric field. It is a scalar quantity, meaning it has magnitude but no direction. Electric potential is measured in volts (V).

What is the relationship between electric potential and electric field?

The electric field at a point is the negative gradient of the electric potential at that point. In other words, the electric field is the rate of change of electric potential in a given direction. This relationship is described by the equation E = -∇V, where E is the electric field, V is the electric potential, and ∇ is the gradient operator.

How is the electric potential calculated?

The electric potential at a point is calculated by dividing the electric potential energy at that point by the amount of charge present. It can also be calculated by integrating the electric field over a distance. The formula for electric potential is V = U/q, where V is the electric potential, U is the electric potential energy, and q is the amount of charge present.

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