Cam Follower Reaction Forces in Accelerating Roller Cart

In summary, the conversation is discussing a problem involving cam followers with diameters of 25mm and 32mm and a mass of 4kg. The question is to determine the reaction forces on all of the cam rollers when a cart accelerates to the right at 20 m/s^2. The given solution is (4kg)(20m/s^2)(.05m)/(.018m) = 222 N on small roller to the right, but it is corrected to be half that. The conversation also discusses other forces and equations related to the problem.
  • #1
DynamicDude
3
0

Homework Statement



Cam followers are 25mm and 32mm in diameter. Mass is 4kg. Determine the reaction forces on all of the cam rollers when cart accelerates to the right at 20 m/s^2

Homework Equations





The Attempt at a Solution


(4kg)(20m/s^2)(.05m)/(.018m) = 222 N on small roller to the right? Is there an equal but opposite force on the large roller too?

 

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  • #2
Where is the force applied that is causing the acceleration?
 
  • #3
assume it is applied 25mm directly below the C.G. (inline with C.G./centered between small rollers)
 
  • #4
Ribbit Ribbit Ribbit...

So I guess there is no one here who knows the answer!??
 
  • #5
Sorry for the delay - for some reason my standard search didn't pick up your earlier reply.
You suggest (4kg)(20m/s^2)(.05m)/(.018m). I think it's only half that.
List all the forces you believe will operate and write down any equations relating them that you can think of.
 

Related to Cam Follower Reaction Forces in Accelerating Roller Cart

1. What is a "Roller Cart dynamics problem"?

A "Roller Cart dynamics problem" is a physics problem that involves studying the motion and behavior of a cart on a track or surface with rollers or wheels. This problem typically involves analyzing the forces and energies acting on the cart and determining its acceleration and velocity.

2. What are the main factors that affect the dynamics of a roller cart?

The main factors that affect the dynamics of a roller cart include the mass of the cart, the mass and distribution of the objects on the cart, the type and size of the wheels or rollers, the surface of the track or ground, and any external forces such as friction or gravity.

3. How do you calculate the acceleration and velocity of a roller cart?

The acceleration and velocity of a roller cart can be calculated using Newton's second law of motion (F=ma) and the equations for motion (v = u + at and s = ut + 1/2at^2), where F is the net force acting on the cart, m is the mass of the cart, a is the acceleration, v is the final velocity, u is the initial velocity, t is time, and s is the displacement.

4. How does the surface of the track or ground affect the dynamics of a roller cart?

The surface of the track or ground can affect the dynamics of a roller cart in several ways. Friction between the wheels or rollers and the surface can affect the speed and motion of the cart. Different surfaces may also have varying levels of smoothness or roughness, which can impact the cart's acceleration and velocity. Additionally, the slope or incline of the surface can influence the direction and magnitude of the forces acting on the cart.

5. What are some real-world applications of roller cart dynamics?

Roller cart dynamics can have various real-world applications, including the design and analysis of amusement park rides, conveyor belts, and transportation systems such as trains and roller coasters. It can also be used in the study of sports equipment, such as skateboards and rollerblades, and in the development of robotics and self-driving vehicles.

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