hndalama said:Homework Statement
A satellite orbits the Earth in a geosynchronous orbit around the equator, meaning that its period is 24 hours and it stays above the same location on Earth at all times. (G = 6.67 x 10⁻¹¹ Nm²/kg².) What is the radius of its orbit?
Homework Equations
GM/r2 = v2/r = w2r
The Attempt at a Solution
I can solve this if the mass of Earth is given but since it isn't I'd like to know if there is a way to solve this without using Earth's mass
Sure, but then re needs to be looked up.lychette said:You know that g = GM/re2, rearrange this to give you the expression for M then go from there
This is, of course, correct. Perhaps the problem should have askedlychette said:If re is not given then an answer can still be obtained in terms of re
to make things clear.What is the radius of its orbit as a fraction of the Earth's radius?
Yes, gravity is a universal force that exists between any two objects with mass. It is not dependent on the Earth's mass alone.
The Earth's mass is one of the factors that determine the strength of gravity. The larger the mass of an object, the stronger its gravitational pull.
No, the Earth's mass is a crucial component in the calculation of gravity. Without it, the strength of gravity cannot be accurately determined.
Yes, we can create artificial gravity through other means such as centrifugal force or electromagnetic force. However, these methods may not be as strong as the Earth's gravitational force.
The presence of other objects in the universe also contributes to the strength of gravity. The more massive an object is, the stronger its gravitational pull on other objects. Therefore, the Earth's mass is not the only factor influencing gravity in the universe.