- #1
joseph9496
- 5
- 0
the question is..
Find the areas of the surfaces generated by revolvin the curves about the indicated axes.
x = (1/3)y^(3/2) - y^(1/2), 1≦y≦3; revolved about y-axis
so i use the general formula "S = Integral 2π (radius)(dS)"
and the radiu in this case is x which is (1/3)y^(3/2) - y^(1/2) but yea..
i just keep getting negative value when i subsitute everything in the equation...
thanks.
Find the areas of the surfaces generated by revolvin the curves about the indicated axes.
x = (1/3)y^(3/2) - y^(1/2), 1≦y≦3; revolved about y-axis
so i use the general formula "S = Integral 2π (radius)(dS)"
and the radiu in this case is x which is (1/3)y^(3/2) - y^(1/2) but yea..
i just keep getting negative value when i subsitute everything in the equation...
thanks.
Last edited: