- #1
PhysKid45
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Homework Statement
Two 10-cm-diameter metal disks separated by a 0.64-mm-thick piece of Pyrex glass are charged to a potential difference of 1100 V .
What is the surface charge density on the disks?
What is the surface charge density on the glass?
Homework Equations
C=(e_0A)/d
C=Q/V
charge density=Q/A
The Attempt at a Solution
Q/V=(e_0A)/d)
Q=((e_0A)/d)*V
charge density= ((e_0A)/d)*V)/A
charge density=(((8.85*10^-12)(pi*.05^2)*1100/.00064)/(pi*.05^2)
I have also tried multiplying the dielectric constant for pyrex (google gave me 4.7) by e_0 and nothing has worked.
I am not sure what the difference between the surface charge density on the glass vs. the disks would be, or how to find it.