Choosing the Correct Momentum Equation: Newtonian vs Relativistic

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In summary, the Newtonian p=mv is an approximation of the relativistic result and is accurate for velocities much smaller than the speed of light. If you are not dealing with objects traveling at relativistic velocities, you will do just fine applying the Newtonian version.
  • #1
Einstein's Cat
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I have come to notice that there are two equations for calculating momentum and I am under the impression that both equations provide different answers.

There is the Newtonian, classical equation of p = mv, where p, is momentum, m is mass, and v is velocity.

Yet also there is the relativistic equation for calculating momentum of p= mv / √ 1 - v squared / c squared, where c is the speed of light.

Therefore, what equation would you recommend to use, and which equation is more accurate?

Thank you for your help and happy holidays!
 
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  • #2
It depends. If you are working with particles traveling at relativistic speeds, then you would need to use the relativistic equation. For particles traveling at velocities much smaller than the speed of light, then you can use the Newtonian approximation. If you want, you can compare the results of two equations for slow moving particles and see for yourself that the results are pretty much exactly the same.
 
  • #3
The Newtonian p = mv is an approximation of the relativistic result and is accurate for velocities much smaller than the speed of light. If you are not dealing with objects traveling at relativistic velocities, you will do just fine applying the Newtonian version.

Einstein's Cat said:
p= mv / √ 1 - v squared / c squared
Just as a heads-up, writing "squared" in an equation tends to severely limit the readability. If you are not yet familiar with writing equations in LaTeX, I suggest you simply use ^ when referring to an exponent. You could also do with a few parentheses. This expression would be much more readable if you wrote it as "p = mv/√(1- v^2/c^2)".
 
  • #4
@Einstein's Cat It would be a good exercise to try calculating the momentum both ways for a few different objects:
- a thrown stone: v=30 meters/sec
- a cannonball: v=300 meters/sec
- a spaceship in orbit: v=9000 meters/sec
- mass-extinction meteorite: v=30000 meters/second

Do this and you'll understand why we still use and teach Newtonian physics. :smile:
 

1. How is Newtonian momentum equation different from relativistic momentum equation?

The Newtonian momentum equation, also known as the classical momentum equation, is based on classical mechanics and describes the relationship between an object's mass, velocity, and its momentum. It does not take into account the effects of high speeds or extreme gravitational forces. On the other hand, the relativistic momentum equation is based on Einstein's theory of relativity and takes into account the effects of high speeds and gravity on an object's momentum.

2. When should I use the Newtonian momentum equation and when should I use the relativistic momentum equation?

The Newtonian momentum equation is appropriate for use in everyday situations where speeds are relatively low and the effects of gravity are negligible. It is also commonly used in engineering and physics applications. The relativistic momentum equation should be used when dealing with extremely high speeds, such as near the speed of light, or in situations where gravity is significant, such as near a black hole.

3. Can the Newtonian and relativistic momentum equations be used interchangeably?

No, the Newtonian and relativistic momentum equations are not interchangeable. They are based on different principles and take into account different factors. Using the wrong equation can lead to incorrect results, particularly in situations involving high speeds or strong gravitational forces.

4. What are the limitations of the Newtonian momentum equation?

The Newtonian momentum equation is limited in its applicability to situations involving high speeds and strong gravitational forces. It also does not accurately describe the behavior of subatomic particles, which require the use of quantum mechanics. Therefore, the Newtonian momentum equation is not suitable for use in all scientific fields.

5. Are there any real-world applications for the relativistic momentum equation?

Yes, the relativistic momentum equation has many real-world applications. It is used in fields such as astrophysics, particle physics, and engineering, where high speeds and strong gravitational forces are a factor. It is also essential in understanding the behavior of subatomic particles and for making precise calculations in advanced technologies, such as GPS systems and particle accelerators.

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