Firstly please use brackets, it looks like it may be ##d_i=\frac{-1}{2d_o}##or ##d_i=\frac{-1}{2}d_o##xamy said:di=-1/2d0
Suraj M said:Firstly please use brackets, it looks like it may be ##d_i=\frac{-1}{2d_o}##or ##d_i=\frac{-1}{2}d_o##
and i don't see the need for the -ve sign in the above equation(logically).
Also because when you substitute the ##h_i## you should negate it as it is inverted, so there shouldn't be a -ve sign for your above equation
A convex mirror is a spherical mirror with a reflective surface that curves outwards. When an object is placed in front of a convex mirror, the light rays from the object are reflected in such a way that they diverge. By tracing these diverging rays back to the mirror, we can determine the apparent size and location of the virtual image formed, which can then be used to calculate the object distance.
The formula for calculating the object distance in a convex mirror is: do = -r2 / (4f), where do is the object distance, r is the radius of curvature of the mirror, and f is the focal length of the mirror.
Yes, the object distance does affect the size of the image formed in a convex mirror. As the object distance increases, the size of the image decreases and vice versa. This is because the image formed by a convex mirror is always virtual, upright, and smaller than the actual object.
No, a convex mirror cannot form a real image. This is because the reflected rays never converge to a point, but always diverge from a virtual image behind the mirror. The image formed by a convex mirror is always virtual, upright, and smaller than the actual object.
The object distance calculation in a convex mirror is reasonably accurate for small objects and small distances from the mirror. However, for larger distances, the calculation may become less accurate due to the simplifying assumptions made in the formula.