Current through a voltmeter with internal resistance

In summary, the conversation discusses a power supply of 10 V connected in series to a 2 ohm resistor and a 5 ohm resistor. The voltage across the 5 ohm resistor is measured using a voltmeter with an internal resistance of 3 ohms. The equivalent resistance of the voltmeter and the 5 ohm resistor is found to be 1.815 ohms, and the voltage across it is calculated to be 4.83 V. The current through the voltmeter is then determined to be either the same as the current through the entire circuit (10/(2 + 1.815)) or just through the voltmeter's 3 ohm internal resistance (1.64 A
  • #1
jumbogala
423
4

Homework Statement


You have a power supply of 10 V. It is connected in series to a 2 ohm resistor and a 5 ohm resistor.

You take the voltage across the 5 ohm resistor with a voltmeter that has an internal resistance of 3 ohms. What is the current through the voltmeter?

Homework Equations


The Attempt at a Solution


So I figured out the equivalent resistance of 5 ohms and 3 ohms is 1.815 ohms. Then the voltage across that is 4.83 V, which is the voltage read by the voltmeter.

Is the current going through the voltmeter just the same as the current going through the entire circuit? (So 10/(2 + 1.815))

Or is it the current just through the voltmeter's 3 ohm internal resistance? (Which I found to be 1.64 A)?
 
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  • #2
Equivalent resistance R = 5*3/8 = ? Check this calculation.
 
  • #3


The current through the voltmeter is the same as the current through the entire circuit. This is because the voltmeter is connected in series with the resistors, so the current flowing through the circuit must also flow through the voltmeter. Therefore, the current through the voltmeter is 10/(2+5+3) = 1.11 A. The 3 ohm internal resistance of the voltmeter does not affect the current flow, as it is in series with the 5 ohm resistor and thus does not change the overall equivalent resistance of the circuit.
 

Related to Current through a voltmeter with internal resistance

1. What is the purpose of a voltmeter with internal resistance?

A voltmeter with internal resistance is used to measure the potential difference or voltage across a circuit component. It is designed to have a high resistance so that it does not draw significant current from the circuit and affect the accuracy of the measurement.

2. How does the internal resistance of a voltmeter affect the measured voltage?

The internal resistance of a voltmeter is typically very high, so it has a minimal effect on the measured voltage. However, it can still create a small voltage drop and lead to a slightly lower measured voltage. This is known as the loading effect of the voltmeter.

3. Can a voltmeter be used to measure current directly?

No, a voltmeter cannot measure current directly. It is designed to measure voltage, and in order to measure current, it needs to be connected in series with a resistor to convert the current into a voltage that can be measured.

4. How can I calculate the actual voltage across a component when using a voltmeter with internal resistance?

To calculate the actual voltage, you need to use the measured voltage and the known internal resistance of the voltmeter. The formula is V_actual = V_measured + (I_measured x R_internal), where V_actual is the actual voltage, V_measured is the measured voltage, I_measured is the measured current, and R_internal is the internal resistance of the voltmeter.

5. Can a voltmeter with internal resistance be used in a circuit with other resistors?

Yes, a voltmeter with internal resistance can be used in a circuit with other resistors. However, it is important to take into account the internal resistance of the voltmeter when calculating the voltage drop across the other resistors in the circuit. This can be done using the formula mentioned in the previous answer.

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